The incremental flux, d²Φ, radiated by dA1 = dx1 dy1 into an element of solid angle dΩ1 = sin θ1 dθ1 df at the entrance pupil of the illumination system is given by
d²Φ = B1(θ1, ø) dA1 sin θ1cosθ1 dθ1 dø
If the system is truly lossless, this incremental flux must pass through an area element dA2 = dx2 dy2 in image space from a solid angle dΩ2 = sin θ2 dθ2 dø, and thus the image radiance in this direction is given by
B2(θ2, ø) = d2Φ ⁄ (dA2 sin θ2 cosθ2 dθ2 dø)
Because the optics of the illumination system are assumed to be lossless all rays passing through must satisfy the Abbe sine theorem
N1dx1 sin θ1 = N2 dx2 sin θ2
And by changing x to y and differentiating
N1dy1 cos θ1 dθ1 = N2 dy2 cos θ2 dθ2
Combining these last three equations results in the general statement of the radiance theorem for an image
B1(θ1, ø) / N12 Ξ B2(θ1, ø) ⁄ N22
Thus no illumination system can produce an image brightness that is greater than that of the initial source. |